"Sun, Hui" <[email protected]> writes: > Here you can see I have 4 processors running at the same time. I read in the > output from MATLAB using the > > command [A,B,C,D,x,b,y] = PetscBinaryRead('binaryoutput'). > > > And I visualize the variable y by the commands: > > mesh(reshape(y(20001:30000),100,100)) > > mesh(reshape(y(10001:20000),100,100)) > > mesh(reshape(y(1:10000),100,100)) > > > The output plots are different from what I get if I use 1 processor.
This example uses a simple decomposition, not what you use above. Note that this example was contributed and we do not endorse it as recommended practice. If your code is already set up very much like this, it may be worth looking at, but don't write new code in this way because it is algorithmically constraining.
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