> On 29 Oct 2018, at 10:56, Matthew Knepley <[email protected]> wrote:
>
> You can certainly map the right edge to the top edge (its topologically a
> square again), but that
> mapping is not smooth, and I do not know how you would make a global basis
> for the approximation space.
Yeah, I thought this was topologically just a cone, but that would have:
u(x=1) = -v(y=1)
and
v(x=1) = u(y=1) (note matching sign).
So if you wanted the v(x=1) = -u(y=1) there would be a twist somehow, and then
a discontinuity in the mapping.
Lawrence
