> On May 16, 2019, at 8:04 PM, Sajid Ali <sajidsyed2...@u.northwestern.edu> > wrote: > > While there is a ~3.5X speedup, deleting the aforementioned 20 lines also > leads the new version of petsc to give the wrong solution (off by orders of > magnitude for the same program). Ok, sorry about this. Unfortunately this stuff has been giving us headaches for years and we are struggling to get it right. > > I tried switching over the the IFunction/IJacobian interface as per the > manual (page 146) which the following lines : It is probably better to not switch to the IFunction/IJacobian, we are more likely to get the TS version working properly. > ``` > TSSetProblemType(ts,TSLINEAR); > TSSetRHSFunction(ts,NULL,TSComputeRHSFunctionLinear,NULL); > TSSetRHSJacobian(ts,A,A,TSComputeRHSJacobianConstant,NULL); > ``` > are equivalent to : > ``` > TSSetProblemType(ts,TSLINEAR); > TSSetIFunction(ts,NULL,TSComputeIFunctionLinear,NULL); > TSSetIJacobian(ts,A,A,TSComputeIJacobianConstant,NULL); > ``` > But the example at src/ts/examples/tutorials/ex3.c employs a strategy of > setting a shift flag to prevent re-computation for time-independent problems. > Moreover, the docs say "using this function (TSComputeIFunctionLinear) is NOT > equivalent to using TSComputeRHSFunctionLinear()" and now I'm even more > confused. > > PS : Doing the simple switch is as slow as the original code and the answer > is wrong as well. > > Thank You, > Sajid Ali > Applied Physics > Northwestern University
Re: [petsc-users] Question about TSComputeRHSJacobianConstant
Smith, Barry F. via petsc-users Thu, 16 May 2019 20:43:01 -0700
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