I have OpenBSD 3.2-stable machine. I'am using it for bridge packet filter. It is very well work. But I receive follow message!. I can't understand
this message. firewall# Mar 6 11:24:33 firwalll /bsd: pf: loose state match: TCP 128.134.54.210:58313 128.134.54.210:58313 65.54.195.190:80 [lo=2772488940 win=17520 modular=1727592950] [lo=2425575762 win=17520 modular=754026801] 10:10 RA seq=2425575762 ack=2567374346 len=0 ackskew=205114594 pkts=11 Why this message is occur? What this mean? Anyone need my rule for understand this message?
