Re: [pgadmin-hackers] pgadminIII on OSX 10.3.9; w/ wxWidgets-2.6.0

[OpenMacNews]

hi,
Hm.. I have no idea what going on here... Is there an autoconf guru here
who might provide insight?
hmmm ... why/where is "pg_debug_build=no" NOT being set ...
do we need an EXPLICIT test for "--disable-debug" to set the NO case?
i'm gonna try this without the --disable-debug flag ...
I just checked - the nightly builds are done with neither "--enable-debug"
nor "--disable-debug" specified, and things work correctly...
well, i just rebuilt w/ NO debug flag in the config, i.e.:
   ./configure \
   --enable-appbundle \
   --enable-static \
   --with-wx=/usr/local/wxWidgets-260 \
   --with-wx-config=wx-config \
   --with-pgsql=/usr/local/pgsql \
   --with-pgsql-include=/usr/local/pgsql/include
NOW, the 'make install' output shows:
   ...
   make  install-exec-hook
   cd /usr/ports/pgadmin3-cvs/pgAdmin3.app/Contents/MacOS ;\
   mv pgadmin3 tmp ;\
   mv tmp pgAdmin3 ;\
       echo no ;\
   if test "no" = "no"; then \
           strip pgAdmin3 ;\
   fi
   no
   ...
AND the executable IS properly stripped:
   % ls -al /usr/ports/pgadmin3-cvs/pgAdmin3.app/Contents/MacOS/pgAdmin3
       -rwxr-xr-x  1 root admin 7767372 Apr 26 10:18
       /usr/ports/pgadmin3-cvs/pgAdmin3.app/Contents/MacOS/pgAdmin3
so, what we're seeing is:
   "./configure --disable-debug", fails to set pg_debug_build=no, i.e. sets = 
yes.

but,
   "./configure" sets it correctly
FYI, configure is autogenerated, and the snipped that checks
for the debug option is found in acinclude.m4 - but it looks
even more correct there (at least for my autoconf-unsavy eyes...)
looking in acinclude.m4:
   ###########################
   # Debug build of pgAdmin3 #
   ###########################
   AC_DEFUN([ENABLE_DEBUG],
   [AC_ARG_ENABLE(debug,
   [ --enable-debug       build a debug version of pgAdmin3],
   [pg_debug_build=yes
   CFLAGS="-Wall -g -O0"
   CXXFLAGS="-Wall -g -O0"],
   [pg_debug_build=no])
   ])
   AC_SUBST(pg_debug_build)
looks ok to me as well ...
ok, this has got to be something obvious/simple, but i'm missing it.
richard
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