Thanks for your response. I sort of figured I was out of luck. As it
turned out, things weren't nearly as bad as they could be - I had turned
on the SQL query echo to the log, so I had a complete trace of all the
statements that had gone into creating that table. It took a few hours'
work, but with some perl, grep, and manual editing I managed to recreate
it.

Thanks, too, for the explanation of why the query worked as it did.

Lessons learned:
- When doing unusual things to the database, do them within a transaction
- Do a formal backup more often

ap

----------------------------------------------------------------------
Andrew J Perrin - http://www.unc.edu/~aperrin
Assistant Professor of Sociology, U of North Carolina, Chapel Hill
[EMAIL PROTECTED] * andrew_perrin (at) unc.edu


On Wed, 30 Oct 2002, Tom Lane wrote:

> Andrew Perrin <[EMAIL PROTECTED]> writes:
> > I just made a mistake that could be quite costly: I did this:
> > update writer_survey set partid='W41308' where survid in (select survid
> > from participants where partid='W41291' limit 1);
> > when I should have done this:
> > update writer_survey set partid='W41308' where survid in (select survid
> > from writer_survey where partid='W41291' limit 1);
> 
> Ooops.
> 
> > Is there any way I can undo this, e.g., set partid back to what it was
> > before I ran this command? I know I should have done it in a transaction,
> > but I didn't.
> 
> You're probably out of luck.  Got a recent backup?
> 
> (If you were really desperate, and haven't yet vacuumed the table, you
> could imagine manually changing the transaction's commit status in
> pg_xlog and then clearing any known-committed status bits in the table.
> But this is ticklish stuff and there are no tools for it that I know of.)
> 
> > More broadly, can someone explain why it worked? There is no survid column
> > in participants, so I would have expected it to generate an error on the
> > sub-select, not match all rows!
> 
> But the sub-select can reference the outer query's variables.  So as
> long as "from writer_survey where partid='W41291'" produced at least
> one row, the sub-select would return the outer value of survid, and
> thus the IN would succeed.
> 
>                       regards, tom lane
> 


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