2008/12/8 ss_postgres <[EMAIL PROTECTED]>:
> Hi,
>
> I am trying to find the position of a character in a string which appears
> multiple times.
>
> The POSITION function returns the position of the character when it first
> occurs.
>
> For eg:
>
> select position ( ' ' in 'Hi How are you');
>
> This returns the result as "3".
>
>
> But i need to result to be
> 3
> 7
> 11
>
>
> Can anyone please let me know what would be the best way to do this.
>
> Thanks
>
My first things:
merlin=> select distinct(x.case) from (select (case when substring('Hi
How are you' from r for 1) = ' ' then r else null end) from
generate_series(0, length('Hi How are you')) as r) as x;
case
------
3
7
11
--
Pawel Socha
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