On Mon, Dec 23, 2024, 09:54 Adrian Klaver <adrian.kla...@aklaver.com> wrote:
> On 12/23/24 08:46, Divyansh Gupta JNsThMAudy wrote: > > Also as you ask how 50 pairs turns into 50 column so each column will be > > a key and the value of that key will store inside their respective > > column for each row > > My problem with understanding this is 50 pairs = 100 values, I don't > understand how that can fit in 50 columns that can only handle 1 value > each. You need to provide some example data showing what you want to > achieve. It does not need to be the full 50, just something to show the > process. > Because the column name is the same as a dictionary key... David J. >
