On Thu, Sep 25, 2008 at 11:01:08AM -0400, Tom Lane wrote: > Louis-David Mitterrand <[EMAIL PROTECTED]> writes: > > critik=# select distinct pt.type_fr,sum(e2.id_event) from person_type > > pt natural join person_to_event join event e using (id_event) LEFT JOIN > > event e2 ON e.id_event = e2.id_event AND e2.id_event=219 join event_type et > > ON e.id_event_type = et.id_event_type where et.type_fr='théâtre' GROUP BY > > pt.type_fr IS NULL; > > > gives this error: > > > ERROR: column "pt.type_fr" must appear in the GROUP BY clause or be > > used in an aggregate function > > > But pt.type_fr is _already_ in the group by. > > No, "pt.type_fr IS NULL" is in the group by. That doesn't ensure that > each group has a unique value of pt.type_fr itself.
Oops, once more I jumped the gun a bit too fast. Thanks for catching it Tom! Best regards, -- Sent via pgsql-general mailing list (pgsql-general@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general