Jef thanks alot for your help.
I appreciate that!
It worked fine.
Dimitris
Quoting "Hoover, Jeffrey" <[email protected]>:
cameradb_dev=# select id, Candidate_pattern
from all_patterns
where :pattern like Candidate_pattern||'%'
and candidate_pattern between substring(:pattern from 1 for 1) and
:pattern
order by length(Candidate_pattern) desc
limit 1;
id | candidate_pattern
----+-------------------
8 | 008925
(1 row)
note 1: bind (or substitute) your value for :pattern
note 2: "and candidate_pattern between..." only helps
if candidate_pattern is indexed, if there aren't
many rows it is not necessary
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of
[email protected]
Sent: Tuesday, December 23, 2008 11:05 AM
To: [email protected]
Subject: [GENERAL] Question about pattern matching
TABLENAME
id Candidate pattern
-------------------------
1 0089258068520
2 008925806852
3 00892580685
4 0089258068
5 008925806
6 00892580
7 0089258
8 008925
9 00892
10 0089
11 008
12 00
13 0
PATTERN
-------
0089257000000
QUESTION
--------
Pls let me know which is the best way to match the
following pattern against this table and Receive id = 8
that is the longest matching pattern from left to right.
BR,
Sakellarios Dimitris.
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