> -----Original Message----- > From: Michael Paquier [mailto:michael.paqu...@gmail.com] > Sent: Mittwoch, 1. Juli 2015 07:05 > To: Marc Mamin > Cc: Postgres General > Subject: Re: [GENERAL] how to extract the page "address" from the ctid > > On Tue, Jun 30, 2015 at 10:56 PM, Marc Mamin <m.ma...@intershop.de> > wrote: > > while waiting for the new BRIN and improved GIN Indexes :-) > > > > I'd like to get a rough feeling, how some column's values are > distributed on the internal pages. > > Is there a quicker way to extract the page reference from the ctid? > > Isn't it something that pageinspect can do directly for you? It has > been extended for brin indexes. > http://www.postgresql.org/docs/devel/static/pageinspect.html > -- > Michael
As I understand it, pageinspect allows to get insight in given pages, but not to compute overall page distribution analysis of given values. There is a function tidsend(tid) that seems to return a row position within a block, but no equivalent to return the block position. I'm fine with my regexp [ substring(ctid::text, '^.([^,]+)') ], but was just wondering if there were a more efficient way for it. This could be a small nice to have e.g. in pageinspect. regards, Marc Mamin -- Sent via pgsql-general mailing list (pgsql-general@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general
