On 29 April 2017 at 11:37, David G. Johnston <david.g.johns...@gmail.com> wrote: >> > Perhaps there are reasons why this optimization is not safe that I >> > haven't >> > thought about? >> >> Yeah, I think so. What happens if an A row cannot find a match in B or >> C? This version of the query will end up returning fewer rows due to >> that, but the original version would consider other rows with a higher >> rank. >> >> We've danced around a bit with using foreign keys as proofs that rows >> will exist for other optimisations in the past, but it's tricky ground >> since foreign keys are not updated immediately, so there are windows >> where they may not actually hold true to their word. > > > I read this query as having a relation cardinality of one-to-one mandatory - > which precludes the scenario described.
What makes you say so? It's pretty easy to show how the queries are not the same. create table a ( id int primary key, b_id int not null, val int not null, rank int not null ); create table b ( id int primary key, c_id int not null, val int not null ); create table c ( id int primary key, val int not null ); insert into a select x,x,x,x from generate_series(1,150) x; insert into b select x,x,x from generate_series(51,150) x; insert into c select x,x from generate_series(51,150) x; SELECT A.val, B.val, C.val FROM A JOIN B ON A.b_id = B.id JOIN C ON B.c_id = C.id ORDER BY A.rank LIMIT 100; -- returns 100 rows SELECT D.val, B.val, C.val FROM (SELECT * FROM A ORDER BY A.rank LIMIT 100) AS D JOIN B ON D.b_id = B.id JOIN C ON B.c_id = C.id LIMIT 100; -- returns 50 rows > Is the above saying that, today, there is no planning benefit to setting up > two deferrable references constraints to enforce the non-optional > requirement? There is no place in the planner where a foreign key is used as a proof that a joined row must exist, with the exception of row estimations for statistics. -- David Rowley http://www.2ndQuadrant.com/ PostgreSQL Development, 24x7 Support, Training & Services -- Sent via pgsql-general mailing list (pgsql-general@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general
