Hi!

On 27.11.2024 16:17, Ravi wrote:

    Please find the patch attached below for your review.

    Thanks & Regards,
    Ravi Revathy
    Member Technical Staff
    ZOHO Corporation




---- On Wed, 27 Nov 2024 18:41:13 +0530 *Ravi <revath...@zohocorp.com>* wrote ---

    Hi Developers,
         Currently, PostgreSQL relies on table statistics, extracted
    within the examine_simple_variable function, to estimate join
    selectivity. However, when dealing with subqueries that include
    GROUP BY clauses even for the single length clauses which result
    in distinct rows, the planner often defaults to an assumption of
    200 distinct rows. This leads to inaccurate cardinality
    predictions, potentially resulting in suboptimal join plans.

    *Problem Example*

    Consider the following query:

    explain select * from t1 left join (select a, max(b) from t2 group
    by a) t2 on t1.a = t2.a;


    The resulting plan predicts a high cardinality for the join, and
    places the larger dataset on the hash side:

     QUERY PLAN
    
--------------------------------------------------------------------------------
    Hash Join  (cost=943037.92..955323.45 rows=6963818 width=16)
       Hash Cond: (t1.a = t2.a)
       ->  Seq Scan on t1 (cost=0.00..289.00 rows=20000 width=8)
       ->  Hash (cost=893538.50..893538.50 rows=3017074 width=8)
             ->  HashAggregate (cost=777429.49..893538.50 rows=3017074
    width=8)
                   Group Key: t2.a
                   Planned Partitions: 64
                   ->  Seq Scan on t2 (cost=0.00..158673.98
    rows=11000098 width=8)
    (8 rows)


    Here, the join cardinality is overestimated, and table t2 with
    larger dataset being placed on the hash side, despite t1 having
    fewer rows.

    *Proposed Solution:*
    In subqueries with a GROUP BY clause that has a single grouping
    column, it is reasonable to assume the result set contains unique
    values for that column.
    By taking this assumption, we can consider the output of the
    aggregate node as unique and instead of assuming a default
    distinct row count (200), we should derive the estimate from the
    HashAggregate node’s row count.

    Execution Plan after the patch applied:

                                      QUERY PLAN
    --------------------------------------------------------------------------
    Hash Join  (cost=777968.49..935762.27 rows=20000 width=16)
       Hash Cond: (t2.a = t1.a)
       ->  HashAggregate (cost=777429.49..893538.50 rows=3017074 width=8)
             Group Key: t2.a
             Planned Partitions: 64
             ->  Seq Scan on t2 (cost=0.00..158673.98 rows=11000098
    width=8)
       ->  Hash  (cost=289.00..289.00 rows=20000 width=8)
             ->  Seq Scan on t1 (cost=0.00..289.00 rows=20000 width=8)
    (8 rows)


    Can you confirm if my assumption about leveraging the distinct row
    property of a GROUP BY clause with a single grouping column for
    improving join cardinality estimation is valid? If not, I would
    appreciate suggestions or corrections regarding this approach.

maybeIrealizedsomethingwaswrong,butI didn'tseea problemwithcardinalitywhenI took outthe problemlikethis:

alena@postgres=# drop table t1; DROP TABLE alena@postgres=# drop table t2; DROP TABLE alena@postgres=# create table t1 (a int); CREATE TABLE alena@postgres=# create table t1 (x int); ERROR: relation "t1" already exists alena@postgres=# create table t2 (a int, b int); CREATE TABLE alena@postgres=# insert into t1 select id from generate_series(1,1000) as id; INSERT 0 1000 alena@postgres=# insert into t2 select id, id%10 from generate_series(991,1900) as id; INSERT 0 910 alena@postgres=# analyze; ANALYZE alena@postgres=# explain analyze select * from t1 left join (select a, max(b) from t2 group by a) t2 on t1.a = t2.a; QUERY PLAN ------------------------------------------------------------------------------------------------------------------- Hash Left Join (cost=39.12..56.76 rows=1000 width=12) (actual time=2.024..2.731 rows=1000 loops=1) Hash Cond: (t1.a = t2.a) -> Seq Scan on t1 (cost=0.00..15.00 rows=1000 width=4) (actual time=0.030..0.259 rows=1000 loops=1) -> Hash (cost=27.75..27.75 rows=910 width=8) (actual time=1.986..1.987 rows=910 loops=1) Buckets: 1024 Batches: 1 Memory Usage: 44kB -> HashAggregate (cost=18.65..27.75 rows=910 width=8) (actual time=1.162..1.586 rows=910 loops=1) Group Key: t2.a Batches: 1 Memory Usage: 169kB -> Seq Scan on t2 (cost=0.00..14.10 rows=910 width=8) (actual time=0.018..0.239 rows=910 loops=1) Planning Time: 0.215 ms Execution Time: 2.926 ms (11 rows)

Cardinality is predicted correctly as I see. I'm missing something?

--
Regards,
Alena Rybakina
Postgres Professional

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