Hi Meskes-san I must use a midrule action like the following that works as expected. I wonder how to write the replacement to ecpg.addons. I think it's impossible, right? Please give me some advice.
PrepareStmt: PREPARE prepared_name prep_type_clause AS { prepared_name = $2; prepare_type_clause = $3; is_in_preparable_stmt = true; } PreparableStmt { $$.name = prepared_name; $$.type = prepare_type_clause; $$.stmt = $6; is_in_preparable_stmt = false; } | PREPARE prepared_name FROM execstring Regards Ryo Matsumura > -----Original Message----- > From: Michael Meskes [mailto:mes...@postgresql.org] > Sent: Friday, March 1, 2019 8:42 PM > To: Matsumura, Ryo/松村 量 <matsumura....@jp.fujitsu.com>; Takahashi, > Ryohei/高橋 良平 <r.takahash...@jp.fujitsu.com>; > 'pgsql-hack...@postgresql.org' <pgsql-hack...@postgresql.org> > Subject: Re: SQL statement PREPARE does not work in ECPG > > Hi Matsumura-san, > > > I will read README.parser, ecpg.addons, and *.pl to understand. > > Feel free to ask, when anything comes up. > > Michael > -- > Michael Meskes > Michael at Fam-Meskes dot De, Michael at Meskes dot (De|Com|Net|Org) > Meskes at (Debian|Postgresql) dot Org > Jabber: michael at xmpp dot meskes dot org > VfL Borussia! Força Barça! SF 49ers! Use Debian GNU/Linux, PostgreSQL >