>       # Avoid bug that converts 'x =- 1' to 'x = -1'

>     $source =~ s!=- !-= !g;


I haven't looked at the shell script this replaces, but is that the correct 
substitution pattern?  (BTW, I'm not seeing the token =- anywhere except in the 
Makefile, which wouldn't be run against, no?  Am I missing something?)

Regards,

David
--
David Christensen
End Point Corporation
da...@endpoint.com





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