On 4/21/17 10:11, Petr Jelinek wrote:
> On 21/04/17 16:09, Peter Eisentraut wrote:
>> On 4/20/17 14:29, Petr Jelinek wrote:
>>> +           /* Find unused worker slot. */
>>> +           if (!w->in_use)
>>>             {
>>> -                   worker = &LogicalRepCtx->workers[slot];
>>> -                   break;
>>> +                   worker = w;
>>> +                   slot = i;
>>> +           }
>>
>> Doesn't this still need a break?  Otherwise it always picks the last slot.
>>
> 
> Yes it will pick the last slot, does that matter though, is the first
> one better somehow?
> 
> We can't break because we also need to continue the counter (I think the
> issue that the counter solves is probably just theoretical, but still).

I see.  I think the code would be less confusing if we break the loop
like before and call logicalrep_sync_worker_count() separately.

> Hmm actually, maybe the if (!w->in_use) should be if (worker == NULL &&
> !w->in_use)?

That would also do it.  But it's getting a bit fiddly.

-- 
Peter Eisentraut              http://www.2ndQuadrant.com/
PostgreSQL Development, 24x7 Support, Remote DBA, Training & Services


-- 
Sent via pgsql-hackers mailing list (pgsql-hackers@postgresql.org)
To make changes to your subscription:
http://www.postgresql.org/mailpref/pgsql-hackers

Reply via email to