On 2017-05-08 09:12:13 -0400, Tom Lane wrote:
> Simon Riggs <si...@2ndquadrant.com> writes:
> > So rearranged code a little to keep it lean.
> Didn't you break it with that?  As it now stands, the memcpy will
> copy the nonzero value.

I've not seen a fix and/or alleviating comment about this so far.  Did I
miss something?

- Andres

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