On Tue, 2 Mar 2004, Joe Conway wrote:
> regression=# select 1 where array[1] in (array[1]);
> ?column?
> ----------
> 1
> (1 row)
>
> regression=# select 1 where array[1] in (array[1,2]);
> ?column?
> ----------
> (0 rows)
The only reason I brought it up was that to me ANY and IN are pretty much
the same kind of operator. Up until now I thought that IN really was the
same as =ANY, but it isn't. I don't like that but of course I have to
accept it. I would rather have had some elem function/operator for arrays
like:
1 ELEM IN array[1,2]
or
1 = ANY ELEM arra[1,2]
But as usual I'm 6 months late with my objections :-)
--
/Dennis Bj�rklund
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