On 12/27/2006 05:19 PM, Tom Lane wrote:
Roman Kononov <[EMAIL PROTECTED]> writes:
On 12/27/2006 03:23 PM, Bruce Momjian wrote:
Are you sure?  As I remember, computation automatically upgrades to
'double'.  See this program and output:


This is platform- and compiler- dependent:

... and probably irrelevant, too.  We should store the result into a
float4 variable and then test for isinf() on that; that eliminates the
question of whether the compiler did the multiply in a wider format or
not.

You are right provided that you want to ignore underflows and silently
produce zeros instead.

If you go this way, I recommend to ignore overflows as well, and silently
produce infinities and NaNs.

Roman

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