On Sat, 20 Jan 2007, Tom Lane wrote:
> Gavin Sherry <[EMAIL PROTECTED]> writes:
> > We want to answer the following: for each employee: what is their rank in
> > terms of salary and what is their rank in terms of age. This query
> > answers that:
>
> > select empno, rank() over (order by salary) as srank,
> > rank() over (order by age) as arank
> > from employees order by empno;
>
> Eeek. This seems like the worst sort of action-at-a-distance. How does
> rank() know what value it's supposed to report the rank of?
This is a frustratingly inconsistent bit of the spec. Rank is defined as
follows:
RANK() OVER WNS is equivalent to:
( COUNT (*) OVER (WNS1 RANGE UNBOUNDED PRECEDING)
- COUNT (*) OVER (WNS1 RANGE CURRENT ROW) + 1 )
Say the salary column has the following values: {100, 200, 200, 300}. This
would give the following output: {1, 2, 2, 4}. DENSE_RANK() would give:
{1, 2, 2, 3}.
These functions are pretty ugly (if you think about them in terms of our
existing aggregates). However, they are by far the most heavily used
window functions (along with ROW_NUMBER()).
Thanks,
Gavin
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