I misunderstood. :)
path '((0,0),(1,0))' is 'closed' path.
in this case, it's maybe operator calculated return length too.
----- Original Message -----
From: "Ioseph Kim" <[EMAIL PROTECTED]>
To: <pgsql-hackers@postgresql.org>
Sent: Saturday, February 03, 2007 6:00 AM
Subject: Re: [HACKERS] problem of geometric operator in v8.2.1
when @-@ operator used at path type,
below query maybe returns 1.
because this path is just line.
----- Original Message -----
From: "Tom Lane" <[EMAIL PROTECTED]>
To: "Ioseph Kim" <[EMAIL PROTECTED]>
Cc: <pgsql-hackers@postgresql.org>
Sent: Saturday, February 03, 2007 5:36 AM
Subject: Re: [HACKERS] problem of geometric operator in v8.2.1
"Ioseph Kim" <[EMAIL PROTECTED]> writes:
=> select @-@ lseg '((0,0),(1,0))';
?column?
----------
1
(1 row)
=> select @-@ path '((0,0),(1,0))';
?column?
----------
2
(1 row)
It's maybe bug in v8.2.1
What do you think is wrong with those answers?
regards, tom lane
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