On 12/27/2006 05:19 PM, Tom Lane wrote:
Roman Kononov <[EMAIL PROTECTED]> writes:
On 12/27/2006 03:23 PM, Bruce Momjian wrote:
Are you sure? As I remember, computation automatically upgrades to
'double'. See this program and output:
This is platform- and compiler- dependent:
... and probably irrelevant, too. We should store the result into a
float4 variable and then test for isinf() on that; that eliminates the
question of whether the compiler did the multiply in a wider format or
not.
You are right provided that you want to ignore underflows and silently
produce zeros instead.
If you go this way, I recommend to ignore overflows as well, and silently
produce infinities and NaNs.
Roman
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