Hello, Consider the following query:
select t1field1, avg(t2fieild2) from t1, t2 where t1.field1 = t2.field2 group by t1field1 That works fine. But I'd really like to see more fields of t1 in this query, however I can't add them into the select because they're not part of the GROUP BY, thus I have to add them to there too: select t1field1, t1field2, t1field3, avg(t2fieild2) from t1, t2 where t1.field1 = t2.field2 group by t1field1, t1field2, t1field3 The problem is that addind them all to GROUP BY causes a performance loss.. The only solution I found is using a subquery like this: select * from t1, (select t1field1, avg(t2fieild2) from t1, t2 where t1.field1 = t2.field2 group by t1field1) t1inner where t1.field1 = t1inner.field1 It works just fine.. But I prefer not to use subqueries unless I am really forced to due to the design of my application. Another solution I considered is using aggreate function like that: select t1field1, max(t1field2), max(t1field3), avg(t2fieild2) from t1, t2 where t1.field1 = t2.field2 group by t1field1 Sadly, this caused the same performance... I wonder though, is it possible to make an aggregate function like first(), last() in Oracle (IIRC)? I believe that in such cases MySQL does first() by itself. Other ideas are welcome too. Regards, Vitaly Belman ICQ: 1912453 AIM: VitalyB1984 MSN: [EMAIL PROTECTED] Yahoo!: VitalyBe ---------------------------(end of broadcast)--------------------------- TIP 3: if posting/reading through Usenet, please send an appropriate subscribe-nomail command to [EMAIL PROTECTED] so that your message can get through to the mailing list cleanly