Try:
SELECT r.id_order FROM report r WHERE r.id_order IN (SELECT id FROM orders WHERE id_status = 6 ORDER BY 1 LIMIT 10 OFFSET 1000) ORDER BY 1
The subquery doesn't *have* to sort because the table is already ordered on the primary key.
You can still add a join to orders outside the subselect without significant cost.
Incidentally, I don't know how you got the first plan - it should include a sort as well.
Andrei Bintintan wrote:
> explain analyze
> SELECT o.id
> FROM report r
> INNER JOIN orders o ON o.id=r.id_order AND o.id_status=6
> ORDER BY 1 LIMIT 10 OFFSET 10
> > Limit (cost=44.37..88.75 rows=10 width=4) (actual time=0.160..0.275 rows=10 loops=1)
> -> Merge Join (cost=0.00..182150.17 rows=41049 width=4) (actual time=0.041..0.260 rows=20 loops=1)
> Merge Cond: ("outer".id_order = "inner".id)
> -> Index Scan using report_id_order_idx on report r (cost=0.00..157550.90 rows=42862 width=4) (actual time=0.018..0.075 rows=20 loops=1)
> -> Index Scan using orders_pkey on orders o (cost=0.00..24127.04 rows=42501 width=4) (actual time=0.013..0.078 rows=20 loops=1)
> Filter: (id_status = 6)
> Total runtime: 0.373 ms
>
> explain analyze
> SELECT o.id
> FROM report r
> INNER JOIN orders o ON o.id=r.id_order AND o.id_status=6
> ORDER BY 1 LIMIT 10 OFFSET 1000000
> Limit (cost=31216.85..31216.85 rows=1 width=4) (actual time=1168.152..1168.152 rows=0 loops=1)
> -> Sort (cost=31114.23..31216.85 rows=41049 width=4) (actual time=1121.769..1152.246 rows=42693 loops=1)
> Sort Key: o.id
> -> Hash Join (cost=2329.99..27684.03 rows=41049 width=4) (actual time=441.879..925.498 rows=42693 loops=1)
> Hash Cond: ("outer".id_order = "inner".id)
> -> Seq Scan on report r (cost=0.00..23860.62 rows=42862 width=4) (actual time=38.634..366.035 rows=42864 loops=1)
> -> Hash (cost=2077.74..2077.74 rows=42501 width=4) (actual time=140.200..140.200 rows=0 loops=1)
> -> Seq Scan on orders o (cost=0.00..2077.74 rows=42501 width=4) (actual time=0.059..96.890 rows=42693 loops=1)
> Filter: (id_status = 6)
> Total runtime: 1170.586 ms
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