Martha Stewart called it a Good Thing when [EMAIL PROTECTED] (Greg Stark) wrote:
> I don't think it would be very hard at all actually.
> It's just a linear algebra problem with a bunch of independent
> variables and a system of equations. Solving for values for all of
> them is a straightforward problem.
> Of course in reality these variables aren't actually independent
> because the costing model isn't perfect. But that wouldn't be a
> problem, it would just reduce the accuracy of the results.
Are you certain it's a linear system? I'm not. If it was a matter of
minimizing a linear expression subject to some set of linear
equations, then we could model this as a Linear Program for which
there are some perfectly good solvers available. (Few with BSD-style
licenses, but we could probably get some insight out of running for a
while with something that's there...)
I think there's good reason to consider it to be distinctly
NON-linear, which makes it way more challenging to solve the problem.
There might well be some results to be gotten out of a linear
approximation; the Grand Challenge is to come up with the model in the
"Tom Christiansen asked me, "Chip, is there anything that you like
that isn't big and complicated?" C++, EMACS, Perl, Unix, English-no, I
guess not." -- Chip Salzenberg, when commenting on Perl6/C++
---------------------------(end of broadcast)---------------------------
TIP 4: Don't 'kill -9' the postmaster