"Kevin Grittner" <kevin.gritt...@wicourts.gov> wrote:
> If you really want the intersection, perhaps:
Or maybe closer:
with x as
(
select
word,
count(*) as countall,
count(case when filetype = 'f' then 1 else null end)
as countf,
count(case when filetype = 's' then 1 else null end)
as counts,
count(case when filetype = 'n' then 1 else null end)
as countn
from unique_words
group by word
)
select word, least(countf, counts, countn) from x
where countf > 0 and counts > 0 and countn > 0
order by word;
Cranked out rather quickly and untested.
-Kevin
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