I think the correct way is

SELECT equipo_attr[1] AS year, equip_attr[2] AS make 
FROM vehicle_tb;

On Mon, 12 Jun 2000, Bernie Huang wrote:

> Hi, I have a following query:
> 
> "select equip_attr[1], equip_attr[2]
> as year, make
> from vehicle_tb;"
> 
> which gives me the following error:
> 
> "ERROR:  Attribute 'make' not found"
> 
> Is there something wrong with my "as" usage?  Thanks
> 
> 
> - Bernie
> 

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