Bladvin,

> I understand why did Jeff's original solution not work. I understand
> why yours do.
> 
> But could you please explain me how the 74000^2 can be calculated
> for this original query?:

Sure.  In Jeff's original query, the updated instance of the table
(sessions2) and the referenced instance (s) are seperate, without any
JOIN or WHERE conditions to link them.  Under these conditions, SQL
engines do a CROSS JOIN, where every single one of the rows in the first
table is matched against every single one of the rows in the second
table.  This gives you a result set of the number of rows in sessions2 *
the number of rows in s.  74,000^2  Get it?

Example:

TableA:
1       A
2       B

Table B
7       H
8       G

SELECT * FROM TableA, TableB
1       A       7       H
1       A       8       G
2       B       7       H
2       B       8       G

-Josh

-Josh


______AGLIO DATABASE SOLUTIONS___________________________
                                       Josh Berkus
  Complete information technology      [EMAIL PROTECTED]
   and data management solutions       (415) 565-7293
  for law firms, small businesses        fax 621-2533
    and non-profit organizations.      San Francisco

---------------------------(end of broadcast)---------------------------
TIP 6: Have you searched our list archives?

http://archives.postgresql.org

Reply via email to