Bladvin, > I understand why did Jeff's original solution not work. I understand > why yours do. > > But could you please explain me how the 74000^2 can be calculated > for this original query?:
Sure. In Jeff's original query, the updated instance of the table (sessions2) and the referenced instance (s) are seperate, without any JOIN or WHERE conditions to link them. Under these conditions, SQL engines do a CROSS JOIN, where every single one of the rows in the first table is matched against every single one of the rows in the second table. This gives you a result set of the number of rows in sessions2 * the number of rows in s. 74,000^2 Get it? Example: TableA: 1 A 2 B Table B 7 H 8 G SELECT * FROM TableA, TableB 1 A 7 H 1 A 8 G 2 B 7 H 2 B 8 G -Josh -Josh ______AGLIO DATABASE SOLUTIONS___________________________ Josh Berkus Complete information technology [EMAIL PROTECTED] and data management solutions (415) 565-7293 for law firms, small businesses fax 621-2533 and non-profit organizations. San Francisco ---------------------------(end of broadcast)--------------------------- TIP 6: Have you searched our list archives? http://archives.postgresql.org