> 
> Consider the following table:
> 
> A     B       C       D       select?
> -------------------------------
> 1     FOO     A1      100     n
> 1     BAR     Z2      100     n
> 2     FOO     A1      101     y
> 2     BAR     Z2      101     y
> 3     FOO     A1      102     y
> 4     BAR     Z2      99      y
> 5     FOO     A1      99      n
> 6     BAR     Z2      98      n
> 7     FOO     AB      103     y
> 7     BAR     ZY      103     y
> 
> This table has the idea of "groups", that is, a group is defined as
> all of the words from B that have the same number A.  The values in
> column C also matter- we want to select both groups A=7 and A=1 since
> they contain different values C.  Note that the groups defined by A=1
> and A=3 are distinct- they do not contain the same number of words
> from B, so we want to select them both.  Also note that D is datetime,
> and all the rows with the same number A will have the same D (this is
> actually ensured by a single row in another table.)
> 
> I want to select all of the numbers A which define distinct groups and
> have the highest datetime D.  Is this possible in a SQL query?
> 
Now that I've read your request more attentively, I understand what 
you want. But I have to admit I have no idea how to word the query, 
I even don't know if it's possible at all. 
Regards, Christoph 

---------------------------(end of broadcast)---------------------------
TIP 2: you can get off all lists at once with the unregister command
    (send "unregister YourEmailAddressHere" to [EMAIL PROTECTED])

Reply via email to