On Wed, 26 Jun 2002 22:18:07 +0200
Dennis Kaarsemaker <[EMAIL PROTECTED]> wrote:

> From a copy of the CDDB-database i want to select the artist & album that
> has on average the longest tracks.
> 
> But in the tracks table there is no such field as length, so i have to
> calculate it. But when i try to do so it just gives me errors.
> 
> This is the erroneous query i have made so far
> 
> select albums.ARTIST, albums.TITLE from tracks,albums
> where tracks.DISCID = albums.DISCID
> group by tracks.DISCID
> having(albums.LENGTH/count(tracks.TRACK)) = 
> (
>   select max(albums.LENGTH/count(tracks.TRACK)) from tracks,albums
>   where tracks.DISCID = albums.DISCID
>   group by tracks.DISCID
> );
> 
> What is the correct way of selecting the album?


As for this query,  some columns, AERIST, TITLE, and LENGTH, are lacking
at the GROUP BY clauses.  Probably, I would think a nearly correct one is
something like the following.


SELECT
     a1.ARTIST, a1.TITLE
FROM 
     (SELECT a0.DISCID, a0.ARTIST, a0.TITLE
        FROM tracks AS t0, albums AS a0
      WHERE t0.DISCID = a0.DISCID
      GROUP BY a0.DISCID, a0.ARTIST, a0.TITLE , a0.LENGTH
      HAVING  a0.LENGTH /COUNT(t0.TRACK)
                  = (SELECT max(mx.average) 
                       FROM (SELECT albums.DISCID,
                                            albums.LENGTH /COUNT(tracks.TRACK)
                                                    AS average
                                       FROM tracks, albums
                                     WHERE tracks.DISCID = albums.DISCID
                                     GROUP BY albums.DISCID, albums.LENGTH
                                  ) AS mx
                     )
    ) AS a1



Regards,
Masaru Sugawara





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