Actually, the ORDER BY *must* be replaced by GROUP BY since it is an
aggregate query.
I have implemented it, and the results are startling, I get the same value
repeated for all projects
i.e.:
AS1 AS1-AJAX/SALEM SIDE 3 0 6 7 30 0 216 240
AU3 AU3-RIVERIDGE/AURORA 3 0 6 7 30 0 216 240
AV1 AVALON 3 0 6 7 30 0 216 240
AW1 AW1-AJAX/WESTNEY SIDE 3 0 6 7 30 0 216 240
AWM AW MORTGAGE 3 0 6 7 30 0 216 240
AX1 AX1-ROSE PETAL VALLEY DEV INC 3 0 6 7 30 0 216 240
And this appears to be the correct data row for a row that is the first
(alphabetically) project that has non zero data in it.
This is the final query, can anyone see anything wrong with it?:
SELECT projects.project_id, projects.marketing_name,
COUNT(lots.lot_id) AS def_count,
COUNT(CASE WHEN dt.days_old_start_date < {d '2002-10-08'}
THEN lots.lot_id ELSE NULL END
) AS def_count_less_30,
COUNT(CASE WHEN dt.days_old_start_date >= {d '2002-10-08'}
AND dt.days_old_start_date < {d '2002-09-08'}
THEN lots.lot_id ELSE NULL END
) AS def_count_30_60,
COUNT(CASE WHEN dt.days_old_start_date >= {d '2002-09-08'}
THEN lots.lot_id ELSE NULL END
) AS def_count_greater_60,
COUNT(DISTINCT(CASE WHEN dt.days_old_start_date < {d '2002-10-08'}
AND dt.deficiency_status_id =
ds.deficiency_status_id
THEN lots.lot_id ELSE NULL END)
) AS lot_count_less_30,
COUNT(DISTINCT(CASE WHEN dt.days_old_start_date >= {d '2002-10-08'}
AND
dt.days_old_start_date < {d '2002-09-08'}
THEN lots.lot_id ELSE NULL END)
) AS lot_count_30_60,
COUNT(DISTINCT(CASE WHEN dt.days_old_start_date >= {d '2002-09-08'}
THEN lots.lot_id ELSE NULL END)
) AS lot_count_greater_60,
COUNT(DISTINCT lots.lot_id) AS lot_count
FROM
(SELECT * FROM deficiency_table) AS dt,
(SELECT * FROM deficiency_status WHERE is_outstanding) AS ds,
(SELECT * FROM projects WHERE division_id = 'GGH') AS proj,
(SELECT * FROM lots) AS lots
WHERE proj.division_id = 'GGH'
AND lots.division_id = proj.division_id
AND lots.project_id = proj.project_id
AND dt.lot_id = lots.lot_id
AND dt.deficiency_status_id = ds.deficiency_status_id
AND ds.is_outstanding
AND lots.project_id = 'EM16'
AND NOT EXISTS (SELECT 1 FROM menu_group_projects WHERE menu_code = 'WA'
AND division_id = proj.division_id AND project_id = proj.project_id AND
status = 'I')
GROUP BY projects.project_id, projects.marketing_name
Terry Fielder
Network Engineer
Great Gulf Homes / Ashton Woods Homes
[EMAIL PROTECTED]
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]]On Behalf Of Christoph Haller
> Sent: Thursday, November 07, 2002 3:57 AM
> To: [EMAIL PROTECTED]
> Cc: [EMAIL PROTECTED]
> Subject: Re: [SQL] query optimization question
>
>
> > SELECT
> > project_id,
> > marketing_name,
> > COUNT(lots.lot_id) AS def_count,
> > COUNT(CASE WHEN dt.days_old_start_date < {d '2002-10-07'}
> > THEN lots.lot_id ELSE NULL END) AS
> def_count_less_30,
> > COUNT(CASE WHEN dt.days_old_start_date >= {d '2002-10-07'}
> > AND dt.days_old_start_date < {d '2002-09-07'}
> > THEN lots.lot_id ELSE NULL END) AS
> def_count_30_60,
> > COUNT(CASE WHEN dt.days_old_start_date >= {d '2002-09-07'}
> > AND dt.days_old_start_date < {d '2002-08-08'}
> > THEN lots.lot_id ELSE NULL END) AS
> def_count_60_90,
> > COUNT(CASE WHEN dt.days_old_start_date >= {d '2002-08-08'}
> > THEN lots.lot_id ELSE NULL END) AS
> def_count_greater_90,
> > COUNT(DISTINCT(CASE WHEN
> > dt.days_old_start_date < {d '2002-10-07'}
> > THEN lots.lot_id ELSE NULL END )) AS
> lot_count_less_30,
> > COUNT(DISTINCT(CASE WHEN
> > dt.days_old_start_date >= {d '2002-10-07'}
> > AND dt.days_old_start_date < {d '2002-09-07'}
> > THEN lots.lot_id ELSE NULL END )) AS
> lot_count_30_60,
> > COUNT(DISTINCT(CASE WHEN
> > dt.days_old_start_date >= {d '2002-09-07'}
> > AND dt.days_old_start_date < {d '2002-08-08'}
> > THEN lots.lot_id ELSE NULL END )) AS
> lot_count_60_90,
> > COUNT(DISTINCT(CASE WHEN
> > dt.days_old_start_date >= {d '2002-08-08'}
> > THEN lots.lot_id ELSE NULL END )) AS
> lot_count_greater_90,
> > COUNT(DISTINCT lots.lot_id) AS lot_count
> > FROM
> > (SELECT * FROM deficiency_table
> > WHERE assigned_supplier_id = '101690') AS dt,
> > (SELECT * FROM deficiency_status
> > WHERE is_outstanding) AS ds,
> > (SELECT * FROM projects
> > WHERE division_id = 'GGH') AS proj,
> > lots
> > WHERE
> > dt.lot_id = lots.lot_id
> > AND lots.division_id = proj.division_id
> > AND lots.project_id = proj.project_id
> > AND dt.deficiency_status_id = ds.deficiency_status_id
> > AND NOT EXISTS
> > (SELECT 1 FROM menu_group_projects
> > WHERE menu_code = 'WA'
> > AND division_id = proj.division_id
> > AND project_id = proj.project_id
> > AND status = 'I')
> > ORDER BY proj.project_id ;
>
> What about simply replacing ORDER BY proj.project_id ; by
> GROUP BY project_id, marketing_name ;
>
> Regards, Christoph
>
>
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