Hi, I've got a table , pdi, with a field pro_id defined as char(25). One fied og this table contains the string '1006666058' plus spaces to fill the 25 length (ie pro_id = '1006666058 '). When I run: select * from pdi where pdi = '1006666058' the row is returned. When I run: select * from pdi where pdi like '1006666058' the row is NOT returned.
select length(pro_id) where pdi = '1006666058' returns: length ----------- 25 2 Row(s) affected 1) In PostgreSQL documentation, it's said that without % wildcards like operates the same as = , it seems not. 2) Why does the = operator return the row ? it shouldn't because of the trailing spaces. 3) The row was inserted from the COPY command: COPY pdi FROM STDIN NULL as '' DELIMITER as '|'; VOL|1006666058|0|PART||PART \. Why does my field contain trailing spaces ? Regards and thanks again for your useful help. PS: create table pdi ( pmf_id char(4) not null , pro_id char(25) not null , lng_id char(3) not null , pdi_desc char(50) not null , pdi_instr text, pdi_matchdesc char(50), CONSTRAINT pk_pdi PRIMARY KEY (pro_id,pmf_id,lng_id) ); Nicolas. --------------------------------------------------------------- Nicolas JOUANIN - SA REGIE FRANCE Village Informatique BP 3002 17030 La Rochelle CEDEX Tel: 05 46 44 75 76 Fax: 05 46 45 34 17 email: [EMAIL PROTECTED] Web : www.regie-france.com --------------------------------------------------------------- ---------------------------(end of broadcast)--------------------------- TIP 9: the planner will ignore your desire to choose an index scan if your joining column's datatypes do not match