'2003-08-04' is ambiguous. It could be a text string, a date, something else. So cast it.
SELECT to_char('2003-08-04'::date, 'Day');
> SELECT to_char(now(), 'Day'); returns Friday as I'd hoped.
> But how do I return the day of the week for a specific date other
> than now()? I'm looking for something along the lines of:
> SELECT to_char('2003-08-04', 'Day') without much success.
>
> Can anyone point me to the right function/combination of functions
> to achieve this?
>
> Thanks!
>
> -----------------------------------------------------------------------
> Thomas Good e-mail: [EMAIL PROTECTED]
> Programmer/Analyst phone: (+1) 718.818.5528
> Residential Services fax: (+1) 718.818.5056
> Behavioral Health Services, SVCMC-NY mobile: (+1) 917.282.7359
>
> // Welches ist das groessere Verbrechen?
> // Massenvernichtungswaffen besitzen oder sie erfinden?
>
>
>
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