When grilled further on (Mon, 19 Jan 2004 00:44:30 -0500), Tom Lane <[EMAIL PROTECTED]> confessed:
> Robert Creager <[EMAIL PROTECTED]> writes: > > ... one piece of data I need is the last value for each GROUP BY > > period. Alas, I cannot figure out how to do this. > > SELECT DISTINCT ON (rather than GROUP BY) could get this done for you. > I had my whine all ready as to how I still couldn't figure it out, when I figured it out: ... SELECT p.period, etday FROM (SELECT DISTINCT ON ( period ) date_trunc( 'hour', "when" ) AS period, etday FROM readings ORDER BY period, "when" DESC) AS p ... Thanks for the tip. Cheers, Rob -- 08:10:55 up 21 days, 21:58, 4 users, load average: 2.15, 2.06, 2.02
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