Hi,  

thanks for the feedback. btw i've run the statement below  & got the following result :

    time_key | yr_id | month_id | month_desc | day_id
              ----------+-------+----------+------------+--------
                      193 |  1994 |               7 |             jul        |     13
(1 row)

actually if i'm going to have a result as below how could i did in my statement ???


          The result should appear as :

                       time_key | yr_id | month_id | month_desc  |day_id
----------+-------+----------+-----------
        1 |  1994 |        1 | Jan                  
        2 |  1994 |        2 | Feb
        3 |  1994 |        3 | Mac
        4 |  1994 |        4 | Apr
        5 |  1994 |        5 | May
        6 |  1994 |        6 | Jun
        7 |  1994 |        7 | July
        8 |  1994 |        8 | Aug
        9 |  1994 |        9 | Sept
       10 |  1994 |       10 | Oct
       11 |  1994 |       11 | Nov
       12 |  1994 |       12 | Dec
       
.
.
.
the data for day_id should be incremental from 1->31 for each month for specific year. meaning to say Every month  should have the day_id
from 1---->31 . (follow exactly the day of the month)
  Time_key    Yr_id    Month_id   Month_desc   Day_id(1-30/31 days)
1
1994
1
Jan
1
2
1994
1
Jan
2
3
1994
1
Jan
3
4
1994
1
Jan
4
5
1994
1
Jan
5
6
1994
1
Jan
6
7
1994
1
Jan
7
8
1994
1
Jan
8
9
1994
1
Jan
9

 
pls guide /help me to solve the above problem . thanks in advance.



Tomasz Myrta <[EMAIL PROTECTED]>

Sent by: [EMAIL PROTECTED]

01/27/2004 10:56 AM CET


        To:        [EMAIL PROTECTED]
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        Subject:        Re: [SQL] time series data



Dnia 2004-01-27 02:42, Użytkownik [EMAIL PROTECTED] napisał:
>
>
> Hi,
>
>    thanks for the info..btw can u pls explain a little bit detail since
> i can't get thru yr solution.
> thanks in advance

insert into time_table (time_key,year_id,month_id,month_desc,day_id)
select
  newid,
  extract('year' from your_date),
  extract('month' from your_date),
  to_char(your_date,'mon'),
  extract('day' from your_date)
  ...
from (select nextval('time_seq') as newid,
'1994-01-01'::date+'1 day'::interval * currval('time_seq') as your_date) x;


Everything you need is to execute query above as many times as you need.

Regards,
Tomasz Myrta

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