Seems a part of your function always returns '0'
select 1 - (to_char(date_trunc('month',now()),'D'))::INT2
because while we use date_trunc it will always return the first day of the
month and when it get subtracted by '1' it be always zero. Is there any
reason why you have included that?
Thanks
Kumar
----- Original Message -----
From: "sad" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, February 16, 2004 6:53 PM
Subject: Re: [SQL] Getting the week of a date
EXCUSE ME, GUYS !
i forgot to add one monome:
7*(((to_char(date_trunc('month',now()),'D'))::INT2-1)/4)
which is stands for skip a first week of month in case it is not consist Wed
finally the select will be similar the following
SELECT 7*(((to_char(date_trunc('month',now()),'D'))::INT2-1)/4) + 1 -
(to_char(date_trunc('month',now()),'D'))::INT2 + 7*3-3 ;
4 - is a number of Wed in a week (in postgresql numeration)
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