Marco Lazzeri <[EMAIL PROTECTED]> writes:
> SELECT
> p.name, ARRAY(SELECT nicknames FROM people WHERE people.id = p.id)
> FROM people AS p
> Any suggestions?
Something like:
db=> create aggregate array_aggregate (basetype = integer, sfunc = array_append, stype
= integer[], initcond = '{}');
CREATE AGGREGATE
db=> select array_aggregate(id) from tab;
array_aggregate
------------------------------------------------------------------------------------------------------------------------------------------------------------
{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,28,29,30,31,32,33,34,36,37,38,39,40,41,42,43,27,26,44,45,46,47,48,49,50,51,52,53,54,35}
(1 row)
--
greg
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