Re: [SQL] Query aid

[Roberto Fichera]

At 12.21 16/12/2004, you wrote:
Am Donnerstag, 16. Dezember 2004 11:34 schrieb Roberto Fichera:
> Hi all,
>
> I have a table acct as (username, terminatedate, terminatecause)
> I would like to build a query which returns three columns orderd by data
> like:
>
> date_trunc( 'day', terminatedate ) | count(cause1) | count(cause2)
>
> where cause1/2 are two type of termination cause from the field
> terminatecause.
>
> for example acct table could be:
>
> user1|01/01/2004 01:01:01| error
> user2|01/01/2004 01:02:01| error
> user1|01/01/2004 02:00:01| normal
> user3|02/01/2004 10:00:01| normal
> user2|02/01/2004 10:10:01| error
>
> I would like to obtain:
>
> date          |normal| error
> 01/01/2004|      1  |   2
> 02/01/2004|      1  |   1
try something like this:
SELECT
  date_trunc( 'day', terminatedate ) AS day,
  SUM(
    CASE
      WHEN cause = 'error'
      THEN 1
      ELSE 0
    END
  ) AS error_count,
  SUM(
    CASE
      WHEN cause = 'normal'
      THEN 1
      ELSE 0
    END
  ) AS normal_count,
FROM acct AS acct1
GROUP BY day
ORDER BY day ASC;
Many thanks! This works well :-)!

kind regards,
janning
Roberto Fichera. 

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