According to the manual at:
http://www.postgresql.org/docs/7.4/static/functions-geometry.html
" The PostgreSQL query planner will consider using an R-tree index whenever an 
indexed column is
involved in a comparison using one of these operators: <<, &<, &>, >>, @, ~=, 
&& (Refer to Section
9.9 about the meaning of these operators.)"

Shouldn't the ~ (contains) operator be included also?
Isn't ~ the commutator of @ ?

I am considering using R-tree's for other-than-geometric purposes.  Here is the 
story:
I have string data (column smiles) which represents chemical structures.  
Comparing strings
for equality works perfectly using an ordinary B-tree index.  But locating 
chemical
substructures requires a more elaborate (read time-consuming) match function.
I search for substructures like this:

 Select count(smiles) from structures where matches(smiles, subsmiles);

where subsmiles is the search pattern desired.  This is not a fast search - 
about
15 seconds for 0.25 million rows.
To speed up this search I have a function (called fingerprint) which produces a 
bit string
representation of some common and uncommon substructures.  I have populated my 
table
with column fp = fingerprint(smiles)
So, this is about 5 times faster:

  Select count(smiles) from structures where
  (fp & fingerprint(subsmiles)) = fingerprint(subsmiles)
  & matches(smiles, subsmiles);
The sequence scan using the first where-clause takes about 3 seconds and the 
final
matches on the resulting subset is insignificant when the subset is small.

But I think I might be able to do better (faster) using R-trees.
Bitstrings can be thought of as "containing" when one bitstring has all the
same bits set as another, even if it has other bits set too - this is the gist 
of the
first where-clause above.

Can I expect to be able to use R-tree's to do this?
Will I simply have to define a new datatype and three R-tree functions
(union, intersection and size).
Will the use of the ~ (contains) operator cause the planner to consider
using an index (this is my first question, way above)?

I hope someone has had the patience and interest to read this far.

Thanks,
TJ



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