On Fri, 6 May 2005 13:34:26 +0530 "Ramakrishnan Muralidharan" <[EMAIL PROTECTED]> wrote:
> SELECT abc.remote_host , c , abc.request_uri , a.t FROM abc , ( select > remote_host , count(*) as c , max( ts ) as t from abc group by remote_host ) > as a > where a.remote_host = abc.remote_host and abc.ts = a.t I thought about this too. But what happens if there are accidentally two sets with same timestamp in the table? I suppose the outer select would match both of them. But a DISTINCT should help to avoid this. Ok, if you think this is the propper way to meet the requirement i will do so. Thank you for your answer! Klaus ---------------------------(end of broadcast)--------------------------- TIP 2: you can get off all lists at once with the unregister command (send "unregister YourEmailAddressHere" to [EMAIL PROTECTED])