The following function takes a table name as a parameter and drops
the table and returns true if there are zero rows (otherwise, it
returns false):
CREATE OR REPLACE FUNCTION dropzero( varchar ) RETURNS bool AS '
DECLARE
zerotable ALIAS FOR $1;
zerocurs refcursor;
rowcount int;
BEGIN
OPEN zerocurs FOR EXECUTE ''SELECT COUNT( * ) FROM '' ||
zerotable;
FETCH zerocurs INTO rowcount;
CLOSE zerocurs;
IF rowcount = 0 THEN
EXECUTE ''DROP TABLE '' || zerotable;
RETURN true;
ELSE
RETURN false;
END IF;
END;
' LANGUAGE 'plpgsql';
-tfo
--
Thomas F. O'Connell
Co-Founder, Information Architect
Sitening, LLC
Strategic Open Source: Open Your i™
http://www.sitening.com/
110 30th Avenue North, Suite 6
Nashville, TN 37203-6320
615-260-0005
On May 24, 2005, at 12:44 PM, CG wrote:
PostgreSQL 7.4 ...
I'm trying to find a way to drop a table via SQL if it contains 0
rows. Here
was my thought:
CREATE OR REPLACE FUNCTION dropif(text, bool)
RETURNS bool AS
'DECLARE
tblname ALIAS FOR $1;
condition ALIAS FOR $2;
BEGIN
IF (condition) THEN
EXECUTE(\'DROP TABLE "\' || tblname || \'";\');
END IF;
RETURN \'t\'::bool;
END;'
LANGUAGE 'plpgsql' VOLATILE;
... then ...
BEGIN;
CREATE TABLE testtbl (i int4);
SELECT dropif('testtbl',(SELECT count(*)::int4 FROM testtbl) = 0);
ERROR: relation 286000108 is still open
CONTEXT: PL/pgSQL function "dropif" line 6 at execute statement
... It makes sense. The select is still open when the table is
going to be
dropped. I need a different strategy.
Please advise!
CG
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