I came into this thread late, so I don't know what you schema looks like.
I have a table that has a timestamp with time zone field and other data. I can write a query that give me a count per day SELECT count(*) AS count, date_trunc( 'day', hour) AS day FROM hist_callhealth GROUP BY day; This will give me a count per day, to get the top X SELECT count, day FROM (SELECT count(*) AS count, date_trunc( 'day', hour) AS day FROM hist_callhealth GROUP BY day) AS foo ORDER BY count desc limit X; Hope this helps, Woody IGLASS Networks -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of A. Kretschmer Sent: Thursday, October 19, 2006 10:18 AM To: pgsql-sql@postgresql.org Subject: Re: [SQL] Grouping by day, limiting amounts am Thu, dem 19.10.2006, um 6:55:41 -0700 mailte chester c young folgendes: > --- "A. Kretschmer" <[EMAIL PROTECTED]> wrote: > > > > I would like to select the 3 (or 10) names with the most votes for > > each day. > > > > > > Any suggestions on how can it be done easily? > > Am I misunderstanding, or can you write a simple: > > select * from <table> where <date>='2006-10-10' > limit 5 order by <vote_ct> desc; >From the first mail: "I would like to select the 3 (or 10) names with the most votes for each day." _FOR_ _EACH_ _DAY_. Your query returns the values only for one day... Andreas -- Andreas Kretschmer Kontakt: Heynitz: 035242/47215, D1: 0160/7141639 (mehr: -> Header) GnuPG-ID: 0x3FFF606C, privat 0x7F4584DA http://wwwkeys.de.pgp.net ---------------------------(end of broadcast)--------------------------- TIP 1: if posting/reading through Usenet, please send an appropriate subscribe-nomail command to [EMAIL PROTECTED] so that your message can get through to the mailing list cleanly ---------------------------(end of broadcast)--------------------------- TIP 3: Have you checked our extensive FAQ? http://www.postgresql.org/docs/faq
