Hi... I tried this its working.. can u please check this. select count(*) as all, sum(decode(entry_user_id,'VC',1)) as entry_user_id,sum(decode(entry_user_id,'VE',1)) as VE ,sum(decode(entry_user_id,CV,1))as CV,sum(decode(entry_user_id,'SC',1))as SC from vigilance_master;
regards penchal -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Karthikeyan Sundaram Sent: Tuesday, February 06, 2007 12:47 PM To: [EMAIL PROTECTED]; pgsql-sql@postgresql.org Subject: Re: [SQL] sql try this: select entry_user_id, sum(decode(entry_user_id,'VC',1,0) as vc, sum(decode(entry_user_id,'VE',1,0) as ve, sum(decode(entry_user_id,'CV',1,0) as cv, sum(decode(entry_user_id,'SC',1,0) as SC from vigilance_master group where entry_user_id=78 group by entry_user_id >From: "Shyju Narayanan" <[EMAIL PROTECTED]> >To: pgsql-sql@postgresql.org >Subject: [SQL] sql >Date: Fri, 2 Feb 2007 13:09:09 +0530 > >Hi All > >this is my table ; >| ID |entry_user_id_int | category_id_chv | >---------------------------------------------- >| 1 | 78 | CV | >---------------------------------------------- >| 2 | 78 | VC | >---------------------------------------------- >| 3 | 78 | CV | >---------------------------------------------- >| 4 | 78 | CV | >---------------------------------------------- >| 5 | 78 | CV | >---------------------------------------------- >| 6 | 78 | CV | >---------------------------------------------- >| 7 | 78 | CV | >---------------------------------------------- >| 8 | 78 | CV | >---------------------------------------------- >| 9 | 78 | VE | >---------------------------------------------- >| 10 | 78 | CV | >---------------------------------------------- >| 11 | 78 | SC | >---------------------------------------------- > >WHEN "select entry_user_id_int, category_id_chv,count(category_id_chv) from >vigilance_master group by category_id_chv,entry_user_id_int having" >entry_user_id_int=78 >result is : > >ID entry_user_id_int category_id_chv count > >1 78 VC 1 >2 78 VE 1 >3 78 CV 8 >4 78 SC 1 > >BUT I NEED THE RESULT AS >entry_user_id_int COUNT(VC) COUNT(VE) COUNT(CV) COUNT(SC) TOTAL >78 1 1 8 1 11 _________________________________________________________________ Get in the mood for Valentine's Day. View photos, recipes and more on your Live.com page. http://www.live.com/?addTemplate=ValentinesDay&ocid=T001MSN30A0701 ---------------------------(end of broadcast)--------------------------- TIP 4: Have you searched our list archives? http://archives.postgresql.org Information transmitted by this e-mail is proprietary to Infinite Computer Solutions and / or its Customers and is intended for use only by the individual or the entity to which it is addressed, and may contain information that is privileged, confidential or exempt from disclosure under applicable law. If you are not the intended recipient or it appears that this mail has been forwarded to you without proper authority, you are notified that any use or dissemination of this information in any manner is strictly prohibited. In such cases, please notify us immediately at [EMAIL PROTECTED] and delete this email from your records. ---------------------------(end of broadcast)--------------------------- TIP 3: Have you checked our extensive FAQ? http://www.postgresql.org/docs/faq
