Thx a lot Chris.
In fact the correct SQL was (rewritten with inner join because of it is
required by my api):
select b1.*
from business b1
inner join (select idnode,max(version_no) as version_no from business
group by idnode) as b2
on b1.idnode = b2.idnode and
(b1.version_no = b2.version_no or b2.version_no is null)
Regards,
Seb.
> -----Message d'origine-----
> De : [EMAIL PROTECTED] [mailto:pgsql-sql-
> [EMAIL PROTECTED] De la part de Christian Kindler
> Envoyé : mercredi 24 octobre 2007 11:55
> À : Sébastien Meudec
> Cc : pgsql-sql@postgresql.org
> Objet : Re: [SQL] get only rows for latest version of contents
>
> Hi!
>
> not quick mut works
>
> select * from business b1
> where b1.version_no = (SELECT max(version_no) FROM business b2.
> where b2.idnode = b1.idnode
> )
>
> If you want to make this quiry faster du a regular join
>
> select b1.*
> from business b1,
> (SELECT max(version_no) FROM business b2.
> where b2.idnode = b1.idnode
> ) as b2
> where b1.idnode = b2.idnode
> and b1.version_no = b2.version_nr
>
> Regards Chris
>
> PS written without running any sql, maybe there are some syntax issues,
> but i am shure you will figure these out :-)
>
>
>
> On Wed, October 24, 2007 11:29 am, Sébastien Meudec wrote:
> > Hi everybody.
> >
> > I have a table like that (i simplified it):
> > CREATE TABLE business {
> > idnode integer not null,
> > version_no integer,
> > c1 text,
> > c2 text,
> > c3 text
> > }
> > With a unique index in (idnode,version_no).
> >
> > This table records many version from contents identified by idnode where
> > texts may be different.
> > So i can have:
> > Idnode | version_no | c1 | c2 | c3
> > 111 | 2 | foo1 | foo2 | foo3
> > 111 | 1 | fee1 | foo2 | foo3
> > 111 | null | fee1 | fee2 | fee3
> > 222 | null | too1 | too2 | too3
> > 333 | 1 | xoo1 | xoo2 | xoo3
> > 333 | null | yoo1 | yoo2 | yee3
> >
> > I want to select all columns but only for last (greatest) version of
> each
> > content. So I want a result like:
> > Idnode | version_no | c1 | c2 | c3
> > 111 | 2 | foo1 | foo2 | foo3
> > 222 | null | too1 | too2 | too3
> > 333 | 1 | xoo1 | xoo2 | xoo3
> >
> > If i do:
> > SELECT idnode, max(version_no) FROM business
> > GROUP BY idnode ORDER BY idnode;
> >
> > I get effectively only last version:
> > Idnode | version_no
> > 111 | 2
> > 222 | null
> > 333 | 1
> >
> > But as soon that i want to get texts, I don't know how to build the SQL.
> > In each SQL i tested i've been forced to put text column in a group by
> > since
> > i used aggregate for version_no:
> > SELECT idnode, max(version_no), c1, c2, c3 FROM BUSINESS
> > GROUP BY idnode, c1, c2, c3 ORDER BY idnode;
> >
> > But with that SQL, because of the group by and different values in text
> i
> > get
> > Idnode | version_no | c1 | c2 | c3
> > 111 | 2 | foo1 | foo2 | foo3
> > 111 | 1 | fee1 | foo2 | foo3
> > 111 | null | fee1 | fee2 | fee3
> > 222 | null | too1 | too2 | too3
> > 333 | 1 | xoo1 | xoo2 | xoo3
> > 333 | null | yoo1 | yoo2 | yee3
> >
> > As we can't do aggregate in join neither in where, i can't get what i
> > want.
> >
> > Anybody could help me to build proper SQL ?
> >
> > Thx for your answers.
> > Sébastien.
> >
> >
> >
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> --
> cu
> Chris
>
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