Andreas Kretschmer wrote on 28.10.2007 12:42:
I have a column with the datatype "text" that may contain leading
whitespace (tabs, spaces newlines, ...) and I would like to remove them all
(ideally leading and trailing).
You can use trim() for that:
select 'x' || trim(both '\t' from trim(both ' ' from ' \t\tfoo bar ')) || 'x';
(for testing with 'x' around the result)
Yes I was thinking about a solution like that as well, but wouldn't that only
work if the order in which spaces and tabs appear is always the same?
The above would replace ' \t' but not '\t ', right?
For regexp_replace() you need an extra parameter 'g' like below:
Cool, works like a charm.
Didn't see that parameter when first reading that chapter.
But it seems my problem was actually caused by something else:
SELECT regexp_replace(myfield, '\s*', '', 'g')
FROM mytable;
does not replace anything, but
SELECT regexp_replace(myfield, '[ \t\n\r]*', '', 'g')
FROM mytable;
does replace all whitespaces (as I expected). And subsequently
SELECT regexp_replace(myfield, '^[ \t\n\r]*', '', 'g')
FROM mytable;
replaces only the whitespace at the beginning.
I thought \s is a "shortcut" for "whitespace", which in my understanding is the
same as [ \t\r\n]. Am I wrong here?
Cheers
Thomas
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