Hmm. Seemed so simple. But how do I get the number of years an interval represents? extract is clearly the wrong way:
stage=# select 'now()-'1987-02-01' as interval,extract(year from now()-'1987-02-01') as age; interval | age --------------------------+----- 7665 days 18:05:51.660345 | 0 select EXTRACT(year FROM INTERVAL '7665 days'); gives the same result. select EXTRACT(day FROM now()-'1987-02-01')/365 as age; seems messy. select (now()-'1987-02-01')/365; gives extraneous junk. Thanks! -- ---- Visit http://www.obviously.com/ ---------------------------(end of broadcast)--------------------------- TIP 4: Have you searched our list archives? http://archives.postgresql.org