I don't understand your count(total) expression... 
It doesnt work, because apparently you dont have any "total" column...
Apparently, you meant count(color)

The problem is that you are grouping by a.org,a.user and on  table "a" u 
actually dont have any "null" users...

Well, if it is to include "null" users, a quick and dirty solution I can think 
of would be to add a "dummy" null user to every diferent org on table a and then
substitute your LEFT OUTER JOIN condition by this one :

from a left  join b

on (a.org = b.org and (a.user = b.user OR (a.user is null and b.user is null )))


Now, I don' know if "null" users on table "a" will violate any constraints you 
may have (e.g. NOT NULL) ...

I know This is not a very elegant solution, but seems to give the results you 
need....

Best,
Oliveiros
  ----- Original Message ----- 
  From: Daniel Hernandez 
  To: pgsql-sql@postgresql.org ; [EMAIL PROTECTED] 
  Sent: Monday, August 18, 2008 5:30 PM
  Subject: Re: [SQL] Join question


  have you tried a right Join?


  Daniel Hernndez.
  San Diego, CA.
  "The more you learn, the more you earn".
  Fax: (808) 442-0427


  -----Original Message-----
  From: "Edward W. Rouse" [EMAIL PROTECTED]
  Date: 08/15/2008 09:48 AM
  To: pgsql-sql@postgresql.org
  Subject: Re: [SQL] Join question


  I have 2 tables, both have a user column. I am currently using a left join 
from table a to table b because I need to show all users from table a even 
those not having an entry in table b. The problem is I also have to include 
items from table b with that have a null user. There are some other criteria as 
well that are simple where clause filters. So as an example:



  Table a:

  Org|user

  A    | emp1

  B    | emp1

  B    | emp2

  B    | emp3

  C    | emp2



  Table b:

  Org|user|color

  A   |emp1|red

  A   |emp1|blue

  A   |null|pink

  A   |null|orange

  B   |emp1|red

  B   |emp3|red

  B   |null|silver

  C   |emp2|avacado



  If I:



  select org, user, count(total)

  from a left join b

  on (a.org = b.org and a.user = b.user)

  where a.org = ‘A’

  group by a.org, a.user

  order by a.org, a.user



  I get:



  Org|user|count

  A    |emp1|2

  A    |emp2|0

  A    |emp3|0



  But what I need is:



  A    |emp1|2

  A    |emp2|0

  A    |emp3|0

  A    |null|2



  Thanks,

  Edward W. Rouse

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