Nicolas Beuzeboc wrote:
Hi,
I was looking for a simple solution to this problem. I can't find a way
to group on b and n by just collapsing sequential n's (identical n's
right next to each other) the sorting condition is the timestamp.
b | n | stamp
----------------------------------------
A | 1 | 2008-09-20 06:07:47.981445 [1]
A | 1 | 2008-09-20 06:08:13.294306 [1]
A | 1 | 2008-09-20 06:12:02.046596 [1]
A | 2 | 2008-09-20 06:12:26.267786 [2]
A | 2 | 2008-09-20 06:12:47.750429 [2]
A | 1 | 2008-09-20 06:13:12.152512 [3]
A | 2 | 2008-09-20 06:13:39.052528 [4]
A | 2 | 2008-09-20 06:14:12.875389 [4]
B | 1 | 2008-09-20 06:14:29.963352 [5]
B | 1 | 2008-09-20 06:14:52.247307 [5]
B | 3 | 2008-09-20 06:15:13.358151 [6]
B | 3 | 2008-09-20 06:15:44.307792 [6]
B | 3 | 2008-09-20 06:16:17.32131 [6]
B | 2 | 2008-09-20 06:16:44.030435 [7]
B | 2 | 2008-09-20 06:17:00.140907 [7]
C | 1 | 2008-09-20 06:17:50.067258 [8]
C | 1 | 2008-09-20 06:18:22.280218 [8]
C | 1 | 2008-09-20 06:18:41.661213 [8]
C | 1 | 2008-09-20 06:19:07.920327 [8]
C | 3 | 2008-09-20 06:19:26.166675 [9]
C | 2 | 2008-09-20 06:19:46.459439 [10]
C | 2 | 2008-09-20 06:20:04.634328 [10]
I'd be tempted to use a set-returning PL/PgSQL function to process an
input set ordered by stamp and return a result whenever the (b,n) pair
changed. I'm sure there's a cleverer set-oriented approach, but it's
eluding me at present.
You need a way to express the notion of "contiguous runs of (b,n)" which
doesn't really exist in (set-oriented) SQL.
Here I give an example of the output I'm looking for, And I can find a
way to do that in crystal report, but I would like postgresql to send it
that way. If the next n is different create a new row.
I suspect that Crystal Reports may be pulling the whole data set from
PostgreSQL then doing its processing client-side.
Try turning on query logging in the server and running your report. See
what SQL Crystal Reports actually executes.
--
Craig Ringer
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