At 11:28 AM 10/23/2008, Joe wrote:
Steve Midgley wrote:
# (invoiceid, txid)
(A, 1)
(A, 3)
(B, 1)
(B, 2)
(C, 5)
(D, 6)
(D, 7)
(E, 8)
(F, 8)
For journalling, I need to group/cluster this together. Is there a
SQL
query that can generate this output:
# (journal: invoiceids, txids)
[A,B] , [1,2,3]
[C], [5]
[D], [6,7]
[E,F], [8]
Hi Dave,
I'm not following the logic here. A has 1,3 and B has 1,2. So why
does the first line print:
[A,B] , [1,2,3]
What's the rule that tells the query to output this way? Is it that
all of B's values are between A's values?
From a purely accounting standpoint, since transaction 1 was applied
to both invoices A and B, you need to group the invoices so that you
can compare total invoiced against total paid.
I tinkered around briefly but didn't come up with a good idea, but I
bet someone on this list can. However, I did create a CREATE script for
your table design which, in my experience, makes it more likely that a
real expert will take on your problem..
Hope this helps,
Steve
DROP TABLE IF EXISTS trans;
CREATE TABLE trans
(
id serial NOT NULL,
inv_id character varying,
tx_id character varying,
CONSTRAINT pk_id PRIMARY KEY (id)
)
WITH (OIDS=FALSE);
insert into trans (inv_id, tx_id) values('A','1');
insert into trans (inv_id, tx_id) values('A','3');
insert into trans (inv_id, tx_id) values('B','1');
insert into trans (inv_id, tx_id) values('B','2');
insert into trans (inv_id, tx_id) values('C','5');
insert into trans (inv_id, tx_id) values('D','6');
insert into trans (inv_id, tx_id) values('D','7');
insert into trans (inv_id, tx_id) values('E','8');
insert into trans (inv_id, tx_id) values('F','8');
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