Thank you very much!
-----Mensaje original-----
De: Pavel Stehule [mailto:pavel.steh...@gmail.com]
postgres=# create or replace function sum_items(bigint[]) returns
bigint as $$ select sum($1[i])::bigint from
generate_series(array_lower($1,1), array_upper($1,1)) g(i)$$ language
sql immutable;
CREATE FUNCTION
Time: 2,510 ms
postgres=# select sum_items(array[1,2,3,4]); sum_items
-----------
10
(1 row)
regards
Pavel Stehule
2009/5/18 Dani Castaños <dcasta...@androme.es>:
> Hi all,
>
> I've this query including arrays:
>
> SELECT hour[1:5], statistics_date
> FROM statistics_daily
> WHERE statistics_date = to_date( '03/01/2008', 'DD/MM/YYYY' )
>
> Result:
>
> hour | statistics_date
> ----------------------------+-----------------
> {1800,1800,1800,1800,1800} | 2008-01-03
>
>
> I'm just wondering if there's some way to retrieve the hour column as the
> sum of the array values... Just like this:
>
> hour | statistics_date
> ----------------------------+-----------------
> 9000 | 2008-01-03
>
>
> Hour is a bigint[] array column.
> My version of postreSQL is 8.1.9
>
> Thank you in advanced!
>
> --
> Dani Castaños Sánchez
> dcasta...@androme.es
>
>
>
> --
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